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Sandeep Garg Solutions Class 11 Economics Chapter 1 – Organisation of Data

Sandeep Garg Class 11 Economics Solutions Chapter 1 Organisation of Data is illustrated by the professional economic educator from the contemporary edition of Sandeep Garg Economics Class 11 textbook solutions.

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There are numerous concepts in economics, but here we provide you with the solution from the Organisation of Data, which will be convenient for the students to score well in the board exams.

Sandeep Garg Solutions Class 11 – Chapter 1

Question 1

Mentioned below are the marks acquired by 40 employees during their assessment. Arrange the marks in ascending and descending order.

10151815965396
221512201564103
2112111931010261910
10172822521178911

Answer:

Marks in Ascending Order:

1,3,3,3,4,5,5,5,6,6,6,8,8,9,9,10,10,10,10,10,10,11,11,12,12,15,15,15,17,17,18,19,19,20,21,21,22,22,26,28

Marks in Descending Order:

28,26,22,22,21,21,20,19,19,18,17,17,15,15,15,12,12,11,11,10,10,10,10,10,10,9,9,8,8,6,6,6,5,5,5,4,3,3,3,1

Question 2

Students height in inches for 36 students are given below. Arrange the following data in an individual frequency sequence.

607268685855507255506666
625566665872726055605558
606672726068555865606855

Answer:

In the form of frequency distribution, the given data can be arranged as follows.

Heights (in inches)MarksFrequency
502
557
584
606
621
651
665
684
726
\(\sum f\) = 36

Question 3

Find out the missing class interval.

Class-IntervalBelow 2020−5050−9090−140More than 140
Frequency8111535

Answer:

In the above-mentioned question, the class interval has a different width. Therefore, the missing class interval cannot be established.

Question 4

Transfer given below cumulative frequency series to simple frequency series.

MarksNo. of Students
Less than 1012
Less than 3019
Less than 5026
Less than 7048
Less than 9057

Answer:

The cumulative frequency ‘less than’ is displayed in ‘simple frequency distribution’ form.

Class-IntervalFrequency
0 – 10

10 – 30

30 – 50

50 – 70

70 – 90

12

19 − 12 = 7

26 − 19 = 7

48 − 26 = 22

57 − 48 = 9

Question 5

From the following data, arrange a frequency distribution table with classes 10-20, 20-30, etc.

25101226103236314155
22313638251112254248
47374554423537326575

Answer:

In the form of frequency distribution, the given data can be arranged as follows.

*Class IntervalTally MarksFrequency
10-205
20-305
30-40 10
40-506
50-602
60-701
70-801
\(\sum f\) = 30

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