NCERT Solutions for Class 8 Chapter 16 Playing with Numbers -Free PDF Download

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Maths Revision Notes for Class 8

NCERT SOLVED

Find the values of the letters in each of the following and give reasons for the steps involved.

1.  

Ans. On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get, 7 + 5 = 12 in which ones place is 2.

A = 7

And putting 2 and carry over 1, we get

B = 6

Hence A = 7 and B = 6

2. 

Ans. On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get,8 + 5 = 13 in which ones place is 3.

 A = 5

And putting 3 and carry over 1, we get

B = 4 and C = 1

Hence A = 5, B = 4 and C = 1

3.  

Ans.  On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get, A x A = 6 x 6 = 36 in which ones place is 6.

 A = 6

Hence A = 6

4.  

Ans. Here, we observe that B = 5

so that 7 + 5 = 12.
Putting 2 at ones place and carry over 1 and A = 2, we get
2 + 3 + 1 = 6

Hence A = 2 and B = 5

5.  

Ans. Here on putting B = 0,

we get 0  3 = 0.

And A = 5, then 5 3 = 15
 A = 5 and C = 1

Hence A = 5, B = 0 and C = 1

6.  

Ans. On putting B = 0, we get 0 , and A = 5, then 5 5 = 25

 A = 5, C = 2

Hence A = 5, B = 0 and C = 2

7.  

Ans.  Here product of B and 6 must be same as ones place digit as B.

6  1 = 6, 6  2 = 12, 6  3 = 18,
6  4 = 24

On putting B = 4, we get the ones digit 4 and remaining two B’s value should be 44.
 For 6  7 = 42  and carry over 2 = 44

Hence A = 7 and B = 4

8.  

Ans. On putting B = 9, we get 9 + 1 = 10

Putting 0 at ones place and carry over 1, we get

For A = 7  7 + 1 + 1 = 9

Hence A = 7 and B = 9

9.  

Ans. On putting B = 7,

 7 + 1 = 8

Now A = 4, then 4 + 7 = 11

Putting 1 at tens place and carry over 1, we get
2 + 4 + 1 = 7

Hence A = 4 and B = 7

10.  

Ans. Putting A = 8 and B = 1, we get

8 + 1 = 9

Now again we add 2 + 8 = 10

Tens place digit is ‘0’ and carry over 1.

Now 1 + 6 + 1 = 8 = A

Hence A = 8 and B = 1