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NCERT Solutions for Class 8 Maths Chapter 16 (Ex 16.1) Playing with Numbers

NCERT Solutions for Class 8 Chapter 16 Playing with Numbers -Free PDF Download

Free PDF download of NCERT Solutions Maths Class 8 Solutions Chapter 16 – Playing with Numbers solved by Expert Maths Teachers on CoolGyan.Org. All Chapter 16 – Playing with Numbers Questions with Solutions for NCERT to help you to revise complete Syllabus and Score More marks.
Maths Revision Notes for Class 8

Chapter NamePlaying with Numbers
ChapterChapter 16
ExerciseExercise 16.1
ClassClass 8
SubjectMaths NCERT Solutions
BoardCBSE
TEXTBOOKCBSE NCERT
CategoryNCERT Solutions

NCERT SOLVED


Find the values of the letters in each of the following and give reasons for the steps involved.

1.  

Ans. On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get, 7 + 5 = 12 in which ones place is 2.

A = 7

And putting 2 and carry over 1, we get

B = 6

Hence A = 7 and B = 6


2. 

Ans. On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get,8 + 5 = 13 in which ones place is 3.

 A = 5

And putting 3 and carry over 1, we get

B = 4 and C = 1

Hence A = 5, B = 4 and C = 1


3.  

Ans.  On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get, A x A = 6 x 6 = 36 in which ones place is 6.

 A = 6

Hence A = 6


4.  

Ans. Here, we observe that B = 5

so that 7 + 5 = 12.
Putting 2 at ones place and carry over 1 and A = 2, we get
2 + 3 + 1 = 6

Hence A = 2 and B = 5


5.  

Ans. Here on putting B = 0,

we get 0  3 = 0.

And A = 5, then 5 3 = 15
 A = 5 and C = 1

Hence A = 5, B = 0 and C = 1


6.  

Ans. On putting B = 0, we get 0 , and A = 5, then 5 5 = 25

 A = 5, C = 2

Hence A = 5, B = 0 and C = 2


7.  

Ans.  Here product of B and 6 must be same as ones place digit as B.

 1 = 6, 6  2 = 12, 6  3 = 18,
 4 = 24

On putting B = 4, we get the ones digit 4 and remaining two B’s value should be 44.
 For 6  7 = 42  and carry over 2 = 44

Hence A = 7 and B = 4


8.  

Ans. On putting B = 9, we get 9 + 1 = 10

Putting 0 at ones place and carry over 1, we get

For A = 7  7 + 1 + 1 = 9

Hence A = 7 and B = 9


9.  

Ans. On putting B = 7,

 7 + 1 = 8

Now A = 4, then 4 + 7 = 11

Putting 1 at tens place and carry over 1, we get
2 + 4 + 1 = 7

Hence A = 4 and B = 7


10.  

Ans. Putting A = 8 and B = 1, we get

8 + 1 = 9

Now again we add 2 + 8 = 10

Tens place digit is ‘0’ and carry over 1.

Now 1 + 6 + 1 = 8 = A

Hence A = 8 and B = 1