# NCERT Solutions class 12 Maths Exercise 2.2 Ch 2 Inverse Trigonometric Functions

## NCERT Solutions for Class 12 Maths Exercise 2.1 Chapter 2 Inverse Trigonometric Functions – FREE PDF Download

NCERT Class 12 Maths Ch 2 is one of the most important ones in the NCERT syllabus. Duly following NCERT Solutions for Class 12 Maths Chapter 2 ensures you that there will be no hindrance when you opt for more advanced branches of Maths. This is where CoolGyan comes in. Our free Class 12 inverse trigonometry solutions will help you understand the chapter thoroughly.

# NCERT Solutions for Class 12 Maths Chapter 2 – Inverse Trigonometric Functions

Prove the following:

1.

Ans. We know that:
Putting

sin3θ=3sinθ4sin3θsin⁡3θ=3sin⁡θ−4sin3θ

Putting ,

Proved.

### 2.

Ans. We know that:

Putting

Putting ,

Proved.

Ans. L.H.S. =

= R.H.S.

Proved.

Ans. L.H.S. =

= R.H.S.

Proved.

### Write the following functions in the simplest form:

5.

Ans. Putting so that

### 6.

Ans. Putting so that

Ans.

### 8.

Ans.

Dividing the numerator and denominator by

[tan(xy)=tanxtany1+tanx.tany][tan⁡(x−y)=tan⁡x−tan⁡y1+tan⁡x.tan⁡y]

### 9.

Ans. Putting  so that

### 10.

Ans.

[Dividing numerator and denominator by ]

Putting so that

11.

Ans.

Ans.

### 13.

Ans. Putting and

Ans. Given:

Ans. Given:

16.

Ans.

Ans.

### 18.

Ans. Putting and so that and

Now, 1925−−−−−√=1625−−√=451−925=1625=45

And

and tany=1coty=23tan⁡y=1cot⁡y=23

### 19.  is equal to:

(A)

(B)

(C)

(D)

Ans.

Therefore, option (B) is correct.

### 20. is equal to:

(A)

(B)

(C)

(D) 1

Ans.

Therefore, option (D) is correct.

### 21. is equal to:

(A)

(B)

(C)

(D)

Ans.

Therefore, option (B) is correct.