NCERT Solutions for Class 12 Maths Exercise 2.1 Chapter 2 Inverse Trigonometric Functions – FREE PDF Download
NCERT Class 12 Maths Ch 2 is one of the most important ones in the NCERT syllabus. Duly following NCERT Solutions for Class 12 Maths Chapter 2 ensures you that there will be no hindrance when you opt for more advanced branches of Maths. This is where CoolGyan comes in. Our free Class 12 inverse trigonometry solutions will help you understand the chapter thoroughly.
NCERT Solutions for Class 12 Maths Chapter 2 – Inverse Trigonometric Functions
Prove the following:
1. 
Putting
sin3θ=3sinθ−4sin3θsin3θ=3sinθ−4sin3θ ⇒⇒ 
Putting ,
Proved.
2. 
Putting 
Putting ,
Proved.
3.
= 
= 
= 
= 
= R.H.S.
Proved.
4.
= 
= 
= 
= 
= 
= R.H.S.
Proved.
Write the following functions in the simplest form:
5. 
so that 
= 
= 
= 
= 
= 
= 
= 
6.
so that 
= 
= 
= 
= 
= 
= 
7.
= 
= 
= 
8.
Dividing the numerator and denominator by 
= 
= 
= 
[tan(x−y)=tanx−tany1+tanx.tany][tan(x−y)=tanx−tany1+tanx.tany]
= 
9.
so that 
= 
= 
= 
= 
=
10.
= 
[Dividing numerator and denominator by 
]
Putting 
so that 
= 
= 
= 
= 
Find the values of each of the following:
11. 
= 
= 
= 
= 
= 
= 
12.
= 
13.
and 
= 
= 
= 
= 
= 
= 
14. If then find the value of
then find the value of 
15. If then find the value of
then find the value of
Find the values of each of the expressions in Exercises 16 to 18.
16. 
= 
= 
= 
= 
17.
= 
= 
= 
= 
= 
18.
and 
so that 
and 
Now, 
= 1−925−−−−−√=1625−−√=451−925=1625=45
And 
and tany=1coty=23tany=1coty=23
= 
= 
= 
= 
= 
19. is equal to:
(A) 
(B) 
(C)
(D) 
=
=
Therefore, option (B) is correct.
20. is equal to:
(A) 
(B) 
(C) 
(D) 1
=
=
=
=
Therefore, option (D) is correct.
21. is equal to:
(A) 
(B) 
(C) 
(D) 
=
=
=
=
=
=
Therefore, option (B) is correct.