NCERT Solutions for Class 11 Biology Chapter 19 Excretory Products and Their Elimination


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Access Answers to NCERT Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

1. Define Glomerular Filtration Rate (GFR)

Solution:

Glomerular Filtration rate (GFR) is the amount of filtrate formed by both the kidneys (nephrons) every minute. The GFR of a healthy person is approximately 125ml per minute. The GFR consists majorly of water and other constituents such as amino acids, glucose, potassium, sodium, urea, uric acid and ketone bodies.

2. Explain the autoregulatory mechanism of GFR.

Solution:

Kidneys regulate the glomerular filtration rate through the mechanism which is auto regulatory. It involves the action of juxtaglomerular apparatus, which is a microscopic structure present between the returning distal convoluted tubule and vascular pole of the renal corpuscle of the same nephron. It regulates the glomerular filtration rate and renal blood flow. When the glomerular filtration rate declines, the juxtaglomerular cells are activated for the release of renin. This triggers the glomerular blood flow causing the GFR to revert to normal. Renin causes GFR to revert to normalcy by activating the renin-angiotensin mechanism.

3. Indicate whether the following statements are true or false:

(a) Micturition is carried out by a reflex.

(b) ADH helps in water elimination, making the urine hypotonic.

(c) Protein-free fluid is filtered from blood plasma into the Bowman’s capsule.

(d) Henle’s loop plays an important role in concentrating the urine.

(e) Glucose is actively reabsorbed in the proximal convoluted tubule.

Solution:

(a) Micturition is carried out by a reflex – True

(b) ADH helps in water elimination, making the urine hypotonic – False

ADH helps in reabsorption of water causing the urine to be hypotonic.

(c) Protein-free fluid is filtered from blood plasma into the Bowman’s capsule – True

(d) Henle’s loop plays an important role in concentrating the urine – True

(e) Glucose is actively reabsorbed in the proximal convoluted tubule – True

4. Give a brief account of the counter current mechanism.

Solution:

The chief adaptation for the conservation of water is the counter current mechanism that is functional inside the kidney. In the kidney there are two counter current mechanisms, namely:

  1. Henle’s loop
  2. Vasa rectae

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  • Henle’s loop is a U-shaped part of the nephron. The flow of blood in the two branches of the tube is in the opposite direction which gives rise to the counter currents.
  • Vasa recta, on the other hand is an efferent arteriole that forms a capillary network around the tubules in the renal medulla which tracks parallel to the Henle’s loop. Vasa recta is also U-shaped. The flow of blood is in opposite directions in the two limbs of vasa recta. Hence, the blood that enters the renal medulla in the descending limb comes in close proximity with the outgoing blood in the ascending limb
  • Through the counter current mechanism, the osmolarity increases in the cortex from 300 mOsmolL-1 to about 1200 mOsmolL-1 in the inner medulla which helps in sustaining the concentration gradient. This in turn aids in the easy movement of water from the collecting tubules. The concentration gradient is due to the movement of urea and NaCl.

5. Describe the role of liver, lungs and skin in excretion.

Solution:

The role of liver, lungs and skin in the process of excretion is as follows:

Liver:

  • It is the chief site for the removal of inactivated products of steroid hormones, cholesterol, drugs and vitamins.
  • Dead erythrocytes possess haemoglobin. This haemoglobin is also disintegrated into bile pigments – biliverdin and bilirubin which are treated wastes.
  • Bile carries substances to the intestine which along with the wastes are eliminated

Lungs:

  • Carbon dioxide is expelled out of the body by the lungs
  • Approximately, it eliminates 200ml of carbon dioxide every minute
  • Water in the form of water vapor is also eliminated
  • Loss of water increases in colder conditions and declines in humid, hot conditions
  • During the process of expiration, several volatile material are also ejected

Skin:

  • It is chiefly responsible for thermoregulation(cooling) of the body
  • Sweat is excreted by the skin. It contains nitrogenous wastes. Sweat is excreted only when necessary, such as to cool the body
  • Sweat is excreted by the sweat glands, constitutes of urea, NaCl and lactic acid
  • Through the sebum, the sebaceous glands removes hydrocarbons, sterols and waxes
  • A protective oily covering is provided to the skin by the sebum

6. Explain micturition.

Solution:

Micturition is the process of releasing urine. Micturition is caused by a neural mechanism known as micturition reflex

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The urinary bladder temporarily stores the urine that is formed. The bladder tends to stretch when the urinary bladder gets filled with urine. This stretching causes to initiate a signal, responding to this signal, the receptors located in the walls of the bladder sends out signals to the central nervous system (CNS). The CNS conveys motor messages that originate the relaxation of the urethral sphincters and the contraction of the smooth muscles of the urinary bladder, thereby resulting in micturition (passing of urine).

7. Match the items of column I with those of column II:

Column IColumn II
(a) Ammonotelism(i) Birds
(b) Bowman’s capsule(ii) Water reabsorption
(c) Micturition(iii) Bony fish
(d) Uricotelism(iv) Urinary bladder
(d) ADH(v) Renal tubule

Solution:

Column IColumn II
(a) Ammonotelism(iii) Bony fish
(b) Bowman’s capsule(v) Renal tubule
(c) Micturition(iv) Urinary bladder
(d) Uricotelism(i) Birds
(d) ADH(ii) Water reabsorption

8. What is meant by the term osmoregulation?

Solution:

Osmoregulation is the process of regulating the osmotic concentration in the cells of the body by checking the quantity of water and salts.

9. Terrestrial animals are generally either ureotelic or uricotelic, not ammonotelic, why?

Solution:

Ammonia is an extremely toxic nitrogenous waste. In order to reduce the toxicity of ammonia in the body, very large amount of water is necessary. To dilute ammonia, the bodies of terrestrial animals do not possess adequate quantity of water. If the body of terrestrial animals stores this excess ammonia, it may turn extremely poisonous for them. Hence in such animals, ammonia is always converted to less toxic uric acid and urea. This is the reason why terrestrial animals are generally either uricotelic or ureotelic.

10. What is the significance of juxta glomerular apparatus (JGA) in kidney function?

Solution:

The juxtaglomerular apparatus is a specialized sensitive region that is formed by the cellular modifications in the distal convoluted tubule and the afferent arteriole at the location of their contact.

Significance:

  • Its mechanism is via the renin-angiotensin-aldosterone system (RAAS)
  • When the glomerular filtration rate dips, the juxtaglomerular apparatus stimulates causing the secretion of renin
  • This renin converts a protein into a peptide, i.e., angiotensinogen to angiotensin
  • Angiotensin is a hormone that elevates the GFR and the flow of blood in these three ways:
    1. Narrowing the efferent arterioles to cause an increase in the glomerular pressure
    2. Triggering the walls of the PCT in order to reabsorb more of water and NaCl
    3. Triggers the adrenal gland to secrete aldosterone that facilitates reabsorption of water and NaCl in the DCT.
  • The volume of blood and blood pressure thereby increases. The hypertonic urine and urine volume decreases.

11. Name the following:

(a) A chordate animal having flame cells as excretory structures

(b) Cortical portions projecting between the medullary pyramids in the human kidney

(c) A loop of capillary running parallel to the Henle’s loop.

Solution:

(a)A chordate animal having flame cells as excretory structures – Amphioxus

Flame cells or protonephridia are the excretory structures found in some animals.

(b)Cortical portions projecting between the medullary pyramids in the human kidney – Columns of

Bertini

The medulla is divided into several conical masses (medulla pyramids) that project into the calyces. The cortex extends in between the medullary pyramids as renal columns known as Columns of Bertini.

(c) A loop of capillary running parallel to the Henle’s loop – Vasa recta

A minute vessel of the network that runs parallel to the Henle’s loop forming a ‘U’ shaped vasa recta. Vasa recta is highly reduced in the cortical nephrons.

12. Fill in the gaps:

(a) Ascending limb of Henle’s loop is ______ to water whereas the descending limb is _______ to it.

(b) Reabsorption of water from distal parts of the tubules is facilitated by hormone _______.

(c) Dialysis fluid contain all the constituents as in plasma except _______.

(d) A healthy adult human excretes (on an average) _______ gm of urea/day

Solution:

  1. Impermeable, permeable
  2. Vasopressin (anti-diuretic hormone)
  3. Nitrogenous waste
  4. 25-30

NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

is categorized under Unit 5 Human Physiology. Apart from thorough preparation students can refer to the previous years’ question papers which has numerous benefits, one of which is it makes students deduce important questions appearing over the years, hence can be well-versed such important questions.

This is where analyzing question papers come in handy. As per previous trends, this unit 5 carries around 18 marks of the total which approximately comes up to 25% of the total weightage. Hence, students must pay extra attention to all the chapters in this unit.

List of subtopics covered in Chapter 19 – Excretory Products and Their Elimination:

NumberSubtopic
19.1Human Excretory System
19.2Urine Formation
19.3Function of the Tubules
19.4Mechanism of Concentration of the Filtrate
19.5Regulation of Kidney Function
19.6Micturition
19.7Role of other Organs in Excretion
19.8Disorders of the Excretory System

NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

Excretion is a basic life process that is carried out by living entities. The Chapter explains about the Human excretory system, its corresponding organs performing respective functions. Some other topics covered are – formation of urine, different functions that the tubules perform, the mechanism of concentration of the filtrate etc. The kidney is a vital organ, it filters the liquid that flows into it. Through this Chapter, students learn how the kidney regulates its functions, how the act of micturition is performed and the significance of related organs in the excretory system.

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Frequently Asked Questions on NCERT Solutions for Class 11 Biology Chapter 19

Why should I learn the Chapter 19 of NCERT Solutions for Class 11 Biology thoroughly?

The Chapter 19 of NCERT Solutions for Class 11 Biology is categorised under Unit 5. Along with the exam preparation, students can also solve previous year question papers which have various advantages. By thorough practice, students will be able to analyse the type of questions that would appear in the Class 11 exam. According to the previous trends, the Unit 5 is around 18 marks which is 25% of the total weightage. So extra attention should be paid towards the chapters present in this unit. The solutions are present in a PDF format which can be used by the students based on their needs.

Does the NCERT Solutions for Class 11 Biology Chapter 19 provide accurate solutions?

The NCERT Solutions for Class 11 Biology Chapter 19 is designed by the academic professionals at CoolGyan’S to help students with their exam preparation. Each and every concept is explained in a simple language which enables students to unlock their own potential. By referring to the NCERT Solutions, students will be able to answer difficult questions effortlessly. Students can also self assess their knowledge about the Chapter and work on them for a better score. The faculty make use of a step wise method of answering questions to help students score well in the annual exam.

Explain the role of lungs in excretion from the Chapter 19 of NCERT Solutions for Class 11 Biology.

1. Lungs help in expelling out the carbon dioxide from our body.
2. Every minute, 200 ml of carbon dioxide is eliminated.
3. Lungs also eliminate water in the form of water vapor.
4. In colder conditions loss of water increases whereas in hot conditions it is declined.
5. Several volatile material are ejected during the process of expiration.