NCERT Solutions for Class 12 Maths Exercise Miscellaneous hapter 7 Integrals – FREE PDF Download
NCERT Solutions for integrals Class 12 exercises Miscellaneous are accessible in PDF format which is available at CoolGyan’s online learning portal. The solutions to this particular exercise from chapter 7 Integrals have been prepared by our experts who have years of experience in this field. Students can find, well-explained solutions to maths problems at CoolGyan’s online learning portal. All the solutions are provided in a way that will help you in understanding the concept effectively. You can download them in PDF format for free.
NCERT Solutions for Class 12 Maths Chapter 7 Integrals (Ex Misc) Exercise Miscellaneous
Evaluate the integrals in Exercises 23 and 24.
23.
Ans. Let I = ……….(i)
Putting
And
=
=
= =
I =
=
=
[Applying Product Rule]
=
=
=
=
=
24.
Ans. Let I =
=
=
=
=
Putting
I =
=
I =
[Applying Product Rule]
I =
=
I =
=
=
Evaluate the definite integrals in Exercise 25 to 33.
25.
Ans. Let I =
=
=
=
=
=
=
= =
26.
Ans. Let I =
I =
[Dividing each term by ]
I =
= ……….(i)
Putting
Limits of integration when and when
I =
=
=
=
27.
Ans. Let I =
=
[Dividing each term by ] ….(i)
Putting
=
Limits of integration when and when
I =
= ……….(ii)
I =
=
I =
=
I =
=
I =
I =
=
28.
Ans. Let I = ……….(i)
Putting
Again
Limits of integration when (say)
where ……….(ii)
when
I = =
= = [From eq. (ii)
29.
Ans. Let I =
=
=
I =
=
=
I =
=
I =
30.
Ans. Let I =
Putting
Again
Limits of integration when and
when
I =
=
=
=
I =
=
I =
=
=
31.
Ans. Let I =
=
Putting
Limits of integration when and when
I =
=
I =
[Applying Product Rule]
I =
=
I =
=
I =
= = =
32.
Ans. Let I =
=
= ……….(i)
I =
= ……….(ii)
Adding eq. (i) and (ii),
2I =
=
=
=
=
=
=
=
=
=
=
=
=
= =
I =
33.
Ans. Let I = ……….(i)
If we get
I =
=
I =
I =
=
I =
I =
=
=
Prove the following (Exercise 34 to 40).
34.
Ans. Let I =
= ……….(i)
Let ……….(ii)
Comparing coefficients of A + C + 0 ……….(iii)
Comparing coefficients of A + B = 0 ……….(iv)
Comparing constants B = 1
On solving eq. (iii), (iv) and (v), we get A = B = 1, C = 1
Putting these values of A, B and C in eq. (ii),
I =
=
I =
=
I =
=
I =
=
=
=
35.
Ans. Let I =
=
[Applying Product rule]
I =
=
= = 1
36.
Ans. Let I =
Here
=
is an odd function of
I = = 0
37.
Ans. Let I =
=
=
I =
=
I =
=
=
38.
Ans. Let I =
=
=
I =
= ……….(i)
Let I1 =
Putting
Limits of integration when and when
I1 =
=
=
Putting value of I1 in eq. (i),
I =
=
=
I =
=
=
=
39.
Ans. Let I =
Putting
Limits of integration when and when , i.e.,
I =
=
=
[Integrating by parts]
I =
=
=
=
40. Evaluate as a limit of sum.
Ans. Given:
Comparing we have,
Putting these values in
I =
=
I =
=
=
I =
=
41. Choose the correct answer:
is equal to:
(A)
(B)
(C)
(D)
Ans. Let I =
=
=
= ……….(i)
Putting
From eq. (i), I =
=
=
Therefore, option (A) is correct.
42. Choose the correct answer:
is equal to:
(A)
(B)
(C)
(D)
Ans. Let I =
=
=
I =
=
Therefore, option (B) is correct.
NCERT Solutions class 12 Maths Miscellaneous Part 2
43. Choose the correct answer:
If then is equal to:
(A)
(B)
(C)
(D)
Ans. Given: ……….(i)
Let I = ……….(ii)
I =
= ……….(iii)
Adding eq. (ii) and (iii),
2I =
=
=
I =
Therefore, option (D) is correct.
NCERT Solutions class 12 Maths Miscellaneous Part 2
44. The value of is:
(A) 1
(B) 2
(C)
(D)
Ans. Let I =
=
=
I =
=
I =
=
I = = 0
Therefore, option (B) is correct.