NCERT Solutions for Class 12 Maths Exercise 9.2 Chapter 9 Differential Equations – FREE PDF Download
Free PDF download of NCERT Solutions for Class 12 Maths Chapter 9 Exercise 9.2 (Ex 9.2) and all chapter exercises at one place prepared by expert teacher as per NCERT (CBSE) books guidelines. Class 12 Maths Chapter 9 Differential Equations Exercise 9.2 Questions with Solutions to help you to revise complete Syllabus and Score More marks.
NCERT Solutions for Class 12 Maths Chapter 9 Differential Equations (Ex 9.2) Exercise 9.2
In each of the Questions 1 to 6 verify that the given functions (explicit) is a solution of the corresponding differential equation:
1.
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To prove: y is a solution of the differential equation ……….(ii)
Proof: From eq. (i), and
∴∴L.H.S. of eq. (ii), = R.H.S.
Hence, y given by eq. (i) is a solution of .
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To prove: y is a solution of the differential equation ……….(ii)
Proof:From, eq. (i),
L.H.S. of eq. (ii),
=
=
= = R.H.S.
Hence, y given by eq. (i) is a solution of .
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To prove: y is a solution of the differential equation ……….(ii)
Proof: From eq. (i),
L.H.S. of eq. (ii),
= R.H.S.
Hence, y given by eq. (i) is a solution of .
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To prove:y is a solution of the differential equation ……….(ii)
Proof: From eq. (i),
= =
= ………(iii)
Now R.H.S. of eq. (ii)
=
= [From eq. (i)]
= =
L.H.S. = R.H.S
Hence, y given by eq. (i) is a solution of .
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To prove:y given by eq. (i) is a solution of differential equation ……….(ii)
Proof: From eq. (i)
L.H.S. of eq. (ii)
= =
=
= R.H.S. of eq. (ii)
y given by eq. (i) is a solution of differential equation
.
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To prove:y given by eq. (i) is a solution of differential equation ..(ii)
Proof: From eq. (i),
=
L.H.S. of eq. (ii)
=
R.H.S. of eq. (ii)
=
= [From eq. (i)]
=
=
=
=
=
L.H.S. = R.H.S
Hence, y given by eq. (i) is a solution of .
In each of the questions 7 to 10, verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:
7.
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To prove:y given by eq. (i) is a solution of differential equation …….(ii)
Proof: Differentiating both sides of eq. (i) w.r.t x, we have
⟹y′=−y2xy−1⟹y′=−y2xy−1
Hence, Function (implicit) given by eq. (i) is a solution of .
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To prove: y given by eq. (i) is a solution of differential equation
……….(ii)
Proof: Differentiating both sides of eq. (i) w.r.t x, we have
……….(iii)
Putting the value of x from eq. (i) and value of y’ from eq. (iii) in L.H.S. of eq. (ii),
= R.H.S. of (ii)
Hence, Function given by eq. (i) is a solution of .
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To prove:y given by eq. (i) is a solution of differential equation ….(ii)
Proof: Differentiating both sides of eq. (i) w.r.t x we have
= eq. (ii)
Hence, Function given by eq. (i) is a solution of
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To prove:y given by eq. (i) is a solution of differential equation ……(ii)
Proof: From eq. (i),
dydxdydx=
= ……….(iii)
Putting the values of y and from eq. (i) and (iii) in L.H.S. of eq. (ii),
=
=
= = R.H.S. of eq. (ii)
Hence, Function given by eq. (i) is a solution of .
Choose the correct answer:
11. The number of arbitrary constants in the general solution of a differential equation of fourth order are:
(A) 0
(B) 2
(C) 3
(D) 4
The number of arbitrary constants ( etc.) in the general solution of a differential equation of
order is
12. The number of arbitrary constants in the particular solution of a differential equation of third order are:
(A) 3
(B) 2
(C) 1
(D) 0
Therefore, option (D) is correct.