NCERT Solutions for Class 12 Maths Exercise 5.3 Chapter 5 Continuity and Differentiability – FREE PDF Download
Free PDF download of NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.3 (Ex 5.3) and all chapter exercises at one place prepared by expert teacher as per NCERT (CBSE) books guidelines. Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.3 Questions with Solutions to help you to revise complete Syllabus and Score More marks.
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.3 (Ex 5.3)
Find in the following Exercise 1 to 15.
1.
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3. 
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dydx(2by+siny)=−adydx(2by+siny)=−a
4. 
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[By Product Rule]
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ddxx3+ddxx2y+ddxxy2+ddxy3=ddx81ddxx3+ddxx2y+ddxxy2+ddxy3=ddx81
dydx=−(3x2+2xy+y2)x2+2xy+3y2dydx=−(3×2+2xy+y2)x2+2xy+3y2
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8. 
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⟹ddx(sin2x)+ddx(cos2y)=ddx(1)⟹ddx(sin2x)+ddx(cos2y)=ddx(1)
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To simplify the given Inverse Trigonometric function, putting
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To simplify the given Inverse Trigonometric function, putting
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Putting
= =
=
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Putting
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=
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=
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=
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13. 
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Putting
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= cos−1(sin2θ)cos−1(sin2θ)
=
=
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Putting
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=
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=
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=
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15. 
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Putting
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y=sec−1(12cos2θ−1)y=sec−1(12cos2θ−1)
=
=
=