NCERT Solutions for Class 12 Maths Exercise 3.1 Chapter 3 – Matrices – FREE PDF Download
NCERT Class 12 Maths Ch 3 is one of the most important ones in the NCERT syllabus. Duly following NCERT Solutions for Class 12 Maths Chapter 3 ensures you that there will be no hindrance when you opt for more advanced branches of Maths. Class 12 Maths Chapter 3 – Matrices solved by Expert Teachers as per NCERT (CBSE) Book guidelines. All Matrices Exercise Questions with Solutions to help you to revise complete Syllabus and Score More marks.
NCERT Solutions for Class 12 Maths Chapter Chapter 3 – Matrices
1. In the matrix A = 
, write:
(i) The order of the matrix.
(ii) The number of elements.
(iii) Write the elements a13,a21,a33,a24,a23a13,a21,a33,a24,a23
Ans. (i) There are 3 horizontal lines (rows) and 4 vertical lines (columns) in the given matrix A.
Therefore, Order of the matrix is 3 x 4.
(ii) The number of elements in the matrix A is 3 x 4 = 12.
(iii) 
Element in first row and third column = 19
Element in second row and first column = 35
Element in third row and third column = 
Element in second row and fourth column = 12
Element in second row and third column = 
2. If a matrix has 24 elements, what are possible orders it can order? What, if it has 13 elements?
Ans. Since, a matrix having 
element is of order 
(i) Therefore, there are 8 possible matrices having 24 elements of orders 1 x 24, 2 x 12, 3 x 8, 4 x 6, 24 x 1, 12 x 2, 8 x 3, 6 x 4.
(ii) Prime number 13 = 1 x 13 and 13 x 1
Therefore, there are 2 possible matrices of order 1 x 13 (Row matrix) and 13 x 1 (Column matrix).
3. If a matrix has 18 elements, what are the possible orders it can have? What if has 5 elements?
Ans. Since, a matrix having element is of order
(i) Therefore, there are 6 possible matrices having 18 elements of orders 1 x 18, 2 x 9, 3 x 6, 18 x 1, 9 x 2, 6 x 3.
(ii) Prime number 5 = 1 x 5 and 5 x 1
Therefore, there are 2 possible matrices of order 1 x 5 (Row matrix) and 5 x 1 (Column matrix).
4. Construct a 2 x 2 matrix A = 
whose elements are given by:
whose elements are given by:
(i) 
(ii) 
(iii) 
Ans. (i) Given: ……….(i)
Putting 
in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
A2 x 2 = 
(ii) Given: ……….(i)
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
A2 x 2 = 
(iii) Given: ……….(i)
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i)
Putting in eq. (i) 
A2 x 2 = 
5. Construct a 3 x 4 matrix, whose elements are given by:
(i) 
(ii) 
Ans. (i) Given: ……….(i)
Putting in eq. (i) 
Putting in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
Putting 
in eq. (i) 
A3 x 4 = 
(ii) Given: ……….(i)
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
Putting in eq. (i) 
A3 x 4 = 
6. Find the values of and from the following equations:
and 
from the following equations:
(i) 
(ii) 
(iii) 
Ans. (i)Given:
By definition of Equal matrices, 
(ii)
Equating corresponding entries, 
……….(i)
……….(ii)
And 
[From eq. (i), 
]
or 
Putting these values of 
in eq. (i), we have 
and 
or x = 4, y=2, z=0
(iii) Given:
Equating corresponding entries, 
……….(i)
………. (ii)
And 
……….(iii)
Eq. (i) – Eq. (ii) = 
9 – 5 = 4
Eq. (i) – Eq. (iii) = 
9 – 7 = 2
Putting values of and 
in eq. (i),
7. Find the values of and from the equation .
and 
from the equation 
.
Ans. Equating corresponding entries,
……….(i)
……….(ii)
……….(iii)
……….(iv)
Eq. (i) – Eq. (ii) = 
Putting in eq. (i), 
Putting in eq. (iii), 
Putting in eq. (iv), 
8. A = is a square matrix if:
is a square matrix if:
(A) 
(B) 
(C) 
(D) None of these
Ans. By definition of square matrix , option (C) is correct.
9. Which of the given values of and make the following pairs of matrices equal:
(A) 
(B) Not possible to find
(C) 
(D) 
Ans. Equating corresponding sides,
And 
Also 
And 
Since, values of are not equal, therefore, no values of and exist to make the two matrices equal.
Therefore, option (B) is correct.
10. The number of all possible matrices of order 3 x 3 with each entry 0 or 1 is:
(A) 27
(B) 18
(C) 81
(D) 512
Ans. Since, general matrix of order 3 x 3 is 
This matrix has 9 elements.
The number of choices for 
is 2 (as 0 or 1 can be used)
Similarly, the number of choices for each other element is 2.
Therefore, total possible arrangements (matrices) = 
times = 
Therefore, option (D) is correct.