NCERT Solutions for Class 10 Maths Exercise 5. Chapter 5 Arithmetic Progressions – FREE PDF Download
NCERT Class 10 Maths Ch 5 is one of the most important ones in the NCERT syllabus. Duly following NCERT Solutions for Class 10 Maths Chapter
5 ensures you that there will be no hindrance when you opt for more advanced branches of Maths. This is where CoolGyan comes in. Our free Class 10 Arithmetic Progressions solutions will help you understand the chapter thoroughly.
NCERT Solutions for Class 10 Maths Chapter 5- Arithmetic Progressions
1. Which term of the AP: 121, 117, 113, ….. is its first negative term?
Here a=121, d=117-121=-4
Now, 
= 
= 
= 
For the first negative term, 
is an integer and 
Hence, the first negative term is 32nd term.
2. The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of sixteen terms of the AP.
Then, 
……….(i)
Also 
Taking 
= 
= 
= 
= 76
Taking 
,
= 
= 
= 
= 20
and 76
3. A ladder has rungs 25 cm apart (see figure). The rungs decrease uniformly in length from 45 cm, at the bottom to 25 cm at the top. If the top and the bottom rungs are 
m apart, what is the length of the wood required for the rungs?
+ 1= 11 The length of the wood required for rungs = sum of 11 rungs
= 112[25+45]112[25+45] = 5.5 ×× 70 = 385 cm
4. The houses of a row are numbered consecutively from 1 to 49. Show that there is a value of 
such that the sum of the numbers of the houses preceding the house numbered is equal to the sum of the numbers of the houses following it. Find this value of 
and 
=
= 
= 
= 
= 
= 49 x 25
According to question,
= 
+ = 
=
Since, is a counting number, so negative value will be neglected.
5. A small terrace at a football ground comprises of 15 steps each of which is 50 m long and built of solid concrete.
Each step has a rise of 
m and a tread of 
m (see figure). Calculate the total volume of concrete required to build the terrace.
Total volume of concrete required = 
= 
= 
= 
= 