NCERT Solutions for Class 10 Maths Exercise 14.2 Chapter 14 Statistics- FREE PDF Download

NCERT Class 10 Maths Ch 14 is one of the most important ones in the NCERT syllabus. Duly following NCERT Solutions for Class 10 Maths
Chapter 14 ensures you that there will be no hindrance when you opt for more advanced branches of Maths. This is where CoolGyan comes in. Our free Class 10 Statistics solutions will help you understand the chapter thoroughly.

NCERT Solutions for Class 10 Maths Chapter 14 – Statistics

1. The following table shows the ages of the patients admitted in a hospital during a year:

Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.

Ans. For Mode: In the given data, maximum frequency is 23 and it corresponds to the class interval 35 – 45.

Modal class = 35 – 45

And and

Mode =

= 35 + 1.8

= 36.8

For Mean:

From given data, Assume mean = 30, Width of the class = 10

Using formula, Mean = 30 + 10 (0.5375) = 30 + 5.375 = 35.37

Hence mode of given data is 36.8 years and mean of the given data is 35.37 years.

Also, it is clear from above discussion that average age of a patient admitted in the hospital is 35.37 years and maximum number of patients admitted in the hospital are of age 36.8 years.

2. The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:

Determine the modal lifetimes of the components.

Ans. Given: Maximum frequency is 61 and it corresponds to the class interval 60 – 80.

Modal class = 60 – 80

And and

Mode =

= 60 + 5.625

= 65.625

Hence modal lifetimes of the components is 65.625 hours.

3. The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also find the mean monthly expenditure:

Ans. For Mode: Here, Maximum frequency is 40 and it corresponds to the class interval 1500 – 2000.

Modal class = 1500 – 2000

And and

Mode =

= 1500 + 347.83

= 1847.83

For Mean:

From given data, Assume mean = 2750, Width of the class = 500

Using formula, Mean = 2750 + 500 (– 0.175) = 2750 – 87.50 = 2662.50

Hence the modal monthly expenditure of family is Rs. 1847.83 and the mean monthly expenditure is Rs. 2662.50.

4. The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.

Ans. For Mode: Here, Maximum frequency is 10 and it corresponds to the class interval 30 – 35.

Modal class = 30 – 35

And and

Mode = =

= = = 30 + 0.625 = 30.63 (approx.)

For Mean:

From given data, Assume mean = 32.5, Width of the class = 5

Using formula, Mean = 32.5 + 5 (– 0.65) = 32.5 – 3.25 = 29.25 (approx.)

Hence mode and mean of given data is 30.63 and 29.25. Also from above discussion, it is clear that states/U.T. have students per teacher is 30.63 and on average, this ratio is 29.25.

5. The given distribution shows the number of runs scored by some top batsmen of the world in one-day cricket matches: