Important Questions for CBSE Class 9 Maths Chapter 15 – Probability


Important Questions for CBSE Class 9 Maths Chapter 15 - Probability

CBSE Class 9 Maths Chapter-15 Important Questions - Free PDF Download

Free PDF download of Important Questions with solutions for CBSE Class 9 Maths Chapter 15 - Probability prepared by expert Mathematics teachers from latest edition of CBSE(NCERT) books. CoolGyan is a platform that provides free NCERT Solutions and other study materials for students. You can download NCERT Solutions for Class 9 Maths to help you to revise the complete Syllabus and score more marks in your examinations. Subjects like Science, Maths, Engish will become easy to study if you have access to NCERT Solution for Class 9 Science, Maths solutions, and solutions of other subjects that are available on CoolGyan only.


1 Marks Questions

1. Out of 35 students Participating in a debate 10 are girls. The Probability that winner is a boy is :

(a) 1 (b) 27 (c) 37 (d) 57

Ans. (d) 57


There are 5 balls, each of the colours white, blue, green, red and yellow in a bag. If 1 balls is drawn from the bag, then the Probability that the ball drawn is red is

(a) 45 (b) 14 (c) 15 (d) 120

Ans. c) 15


3.If P(e)= 0.25 what is the value of P(not E)

(a) 0.5 (b) 1 (c) 0 (d) 0.75

Ans. (d) 0.75


4.Sum of the probabilities of all events of a trial is

(a) less than 1 (b) greater than 1 (c) lies between 0 and 1 (d) 1

Ans. d) 1


5. A four digit number is to be formed by using the digits 2, 4, 7, 8. The probability that the number will start with 7 is

(a) 34 (b) 14 (c) 13 (d) 17

Ans. (b) 14


6. The probability of an event of a trial :

(a) is 1 (b) lies between 0 and 1 (both inclusive)

(c) is 0 (d) is greater than 1

Ans. (b) lies between 0 and 1 (both inclusive)


7. A die is thrown once, the probability of getting a prime number on the die is :

(a) 16 (b) 13 (c) 12 (d) 23

Ans. (c) 12


8. If two coins are tossed, then the probability of getting no tail is :

(a) 14 (b) 14 (c) 15 (d) 34

Ans. (b) 14


9. If is dice is thrown once what is the probability of getting an even prime number.

(a) 16 (b) 12 (c) 23 (d) 1

Ans. 16


10. A card is drawn from a pack of 52 cards what is the probability of getting an non ace card.

(a) 113 (b) 1213 (c) 14 (d) none of these

Ans. 1213


11. The minimum value of probability is

(b) 12 (c) 0 (d) none of these

Ans. 0


12. Performing an experiment once is called

(a) Trial (b) Event (c) Probability (d) none of these

Ans. Trial


13. What is the probability of a number greater than 6 for a single throw of a die?

(a) 0 (b) 1 (c) 12 (d) none of these

Ans. 0


14. If P(E)=34what is value ofP(E¯).

(a) 34 (b) 14 (c) 1 (d) none of these

Ans. 14


15. A card is drawn from a pack of 52 playing cards. What is the probability of getting an king of black colour

(a) 126 (b) 452 (c) 14 (d) none of these

Ans. 126


16. A coin is tossed 2 times what is the probability of getting at most 2 heads.

(a) 34 (b) 12 (c) 14 (d) none of these

Ans. None of these


2 Marks Questions

1. A teacher analyses the performance of two sections of students in a mathematics test of 100 marks given in the following table:

 

No. of students

0 – 20

20 – 30

30 – 40

40 – 50

50 – 60

60 – 70

70 and above

7

10

10

20

20

15

8

total

90

1. Find the probability that a student obtained less than 20% in the mathematics test.
2. Find the probability that a student obtained 60 or above.

Ans. (i)No. of students obtaining marks less than 20 out of 100, i.e. 20% = 7

Total students in the class = 90

P (A student obtained less than 20%) = 790

P (A student obtained marks 60 or above) = 2390


2. To know the opinion of the students about the subject statistics, a survey of 200 students was conducted. The data is recorded in the following table:

Opinion

No. of students

likes

dislikes

135

65

Find the probability that a student chosen at random:

(i) likes statistics (ii) dislikes it.

Ans. Total no. of students on which the survey about the subject of statistics was conducted = 200

i) No. of students who like statistics = 135

P (a student likes statistics) = 135200=2740

ii) No. of students who do not like statistics = 65

P (a student does not like statistics) = 65200=1340


3. Refer Q.2, Exercise 14.2. What is the empirical probability than an engineer lives:

  1. less than 7 km from her place of work?
  2. more than or equal to 7 km from her place of work?
  3. within 12km from her place of work?

Ans. Total number of engineers = 40

i) No. of engineers living less than 7 km from her place of work = 9

P (Engineer living less than 7 km from her place of work) = 940

ii) No. of engineers living more than or equal to 7 km from her place of work =

P ( Engineer living more than or equal to 7 km from her place of work) = 2140

(iii) No. of engineers living within km from her place of work = 0

P ( Engineer living within 12 km from her place of work) = 040= 0


4. Activity: Note the frequency of two wheelers, three wheelers and four wheelers going past during a time interval, in front of your school gate. Find the probability that any one vehicle out of the total vehicles you have observed is a two wheeler.

Ans. Let you noted the frequency of types of wheelers after school time (i.e. 3 pm to 3.30 pm) for half an hour.

Let the following table shows the frequency of wheelers.

Types of wheelersFrequency of wheelers
Two wheelers125
Three wheelers45
Four Wheelers30

Probability that a two wheelers passes after this interval =


5. Activity: Ask all the students in your class room to write a 3-digit number. Choose any student from the room at random. What is the probability that the number written by him is divisible by 3, if the sum of its digits is divisible by 3.

Ans. Let number of students in your class is 24.

Let 3-digit number written by each of them is as follows:

837, 172, 643, 371, 124, 512, 432, 948, 311, 252, 999, 557, 784, 928, 867, 798, 665, 245, 107, 463, 267, 523, 944, 314

Numbers divisible by 3 are = 837, 432, 948, 252, 999, 867, 798 and 267

Number of 3-digit numbers divisible by 3 = 8

P (3-digit numbers divisible by 3) = 824=13


6. Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of four (in kg):4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00

Find the probability that any of these bags chosen at random contains more than 5 kg of flour.

Ans. Number of bags containing more than 5 kg of wheat flour = 7

Total number of wheat flour bags = 11

P (a bag containing more than 5 kg of wheat flour) = 711


7. In Q.5, Exercise 14.2, you were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 – 0.16 on any of these days.

Ans. From the frequency distribution table we observe that:

No. of days during which the concentration of sulphur dioxide lies in interval 0.12 – 0.16 = 2

Total no. of days during which concentration of sulphur dioxide recorded = 30

P (day when concentration of sulphur dioxide (in ppm) lies in 0.12 – 0.16) = 230=115


8. In Q.1, Exercise 14.1 you were asked to prepare a frequency distribution table regarding the blood groups of 30 students of a class. Use this table to determine the probability that a student of this class selected at random has blood group AB.

Ans. From the frequency distribution table we observe that:

Number of students having blood group AB = 3

Total number of students whose blood group were recorded = 30

P (a student having blood group AB) = 330=110


9. A die is thrown 1000 times with the frequencies for the outcomes 1, 2, 3, 4, 5 and 6 as given in the following table:

Outcome123456
Frequency179150157149175190

Find the probability of getting each outcome.

Ans. (i) No. of outcome getting no. 1 = 179

P(1)=1791000=0.179

(ii) Probability of outcome 2­­

P(2)=1501000=0.15

(iii) Probability of outcome 3

P(3)=1571000=0.157

(iv) Probability of outcome 4

P(4)=1491000=0.149

(v) Probability of outcome 5

P(5)=1751000=0.175

(vi) Probability of outcome 6

P(6)=1901000=0.19


10. Two coins are tossed 729 times and the out comes are:

No tail: 189, One tail: 297, Two tails: 243

Find the Probability of the occurrence of each of these events.

Ans. No. of total trials = 729

E1, E2 and E3 are events getting no tail, one tail and two tails, then

P(E1)=189729=727P(E2)=297729=1127

P(E3)=243729=13


11. A bag contains 15 cards bearing numbers 1, 2, 3, 4, ……….. , 14, 15. A card is drawn from the bag. Find the Probability that it bears :

(i) a Prime number (ii) A number divisible by 2

Ans. Total number of cards = 15

No. of total trials = 15

(i) Among 1, 2, 3, 4,……., 14,15, prime number are 2, 3, 5, 7, 11, 13

Number of favourable outcomes = 6

P (Prime number) = 615=25

(ii) Among 1, 2, 3, 4, ………….., 14, 15

No. divisible by 2 are 2, 4, 6, 8, 10, 12, 14

Number of outcomes = 7

P (no. divisible by 2) = 715


12. A coin is tossed 400 times and outcomes are

Tail: 230 Head:170

Ans. (i) Total outcomes = 400

Head = 170

P(H)=170400=1740

(ii) Tail = 230

P(T)=230400=2340


13. A survey of 200 students was conducted to check the opinion of students about the topic geometry. It was found that 175 students do not like geometry. Find the probability of the students who like geometry.

Ans. Total no. of Students = 200

The no. of students do not like geometry = 175

The no. of students who like geometry = 200-175=25

P (no. of students who like geometry) = 25200

=540=18


14. Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes.

Outcomes3 heads2 heads1 headsNo head
Frequency23727728

Compute the probability of 2 heads coming up.

Ans. Total number of tosses = 200

Number of outcomes of 2 heads = 72

P (2 heads) =72200=925


15. The heights of 70 students are given in the following table.

Heights (in cm)150160158155164168
No. of students1014815716

Find the probability that a student has height.

(i) 169 cm (ii) Less than 150 cm

Ans. (i) Total no. of students = 70

No. of total trial =70

The no. of students has height 169 cm = 0

P (a student has a height 169 cm) = 070=0

(ii) No. of students has height less than 150 cm = 0

P (a student has a height less than 150 cm) = 070=0


16. A bag contains 20 cards numbered from 1 to 20 one card is drawn from the bag. Find the probability that it bears a prime number.

Ans. Total no. of cards = 20

No. marks on the cards are 1, 2, 3, 4, 5, 6, …………… , 20

Prime numbers are {2, 3, 5, 7, 11, 13, 17, 19}

Total prime numbers = 8

P (a prime no.) = 820=25


17. Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes

Outcomes3 heads2 heads1 headsNo head
Frequency23727728

Compute the probability of 2 heads coming up

Ans. Total no. of tosses = 200

No. of outcomes of 2 heads = 72

P (2 heads) =72200=925


18. A die is thrown once. Find the probability of getting (i) an odd number (ii) a number greater than one.

Ans. If a die is thrown once, total possible outcomes are S={1,2,3,4,5,6,}

E=an odd no i)E={1,3,5}n(E)=3, n(S)=6P(E)=n(E)n(S)=36=12

(ii) a no. greater than one


19. Two coins are tossed 340 times and the outcomes are

(i) Two tail =115 (ii) one tail =100 (iii) no tail =125

Find the probability of occurrence of (i) one tail (ii) three tail

Ans. Total possible outcomes = 340

(i) Occurrence of one tail = 100

P(E)=100340=517

(ii) Occurrence of three tails = 0

P(E)=0340=0


20. To know the option of the students about the subject mathematics a survey of 200 students was conducted. The obtained data is given below.

OpinionNo. of students
like135
dislike65

(i) like mathematicsFind the probability that a student chosen at random

(ii) does not like it

Ans. Total number of students are 200

(i) No. of students like mathematics = 135

P(E)=135200=2740

(ii) No. of students dislike mathematics = 65

P(E¯)=65200=1340


21. Out of 17 boys and 13 girls of a class, 1 student is to be selected. Find the probability of selecting a girl

Ans. Total no. of students = 17+13=30

No. of girls = 13

P (a student selecting a girl) = 1330


22. A bag contains 5 white, 4 red and 3 black balls. A ball is drawn from the bag, find the probability that it is not black

Ans. No. of white balls = 5

No. of red balls = 4

No. of black balls = 3

Total no. of balls = 5+4+3 = 12

P (Black balls) = 312=14

P (the ball is not black) = 114=34


23. A card is drawn from a 52 pack of cards. Find the probability that it is a queen

Ans. Total no. of cards =52

No. of queens = 4

P (getting a queen) = 452=113


24. There are 500 tickets of a lottery out of which 10 are prize winning tickets. A person buys one ticket. Find the probability that he gets a prize winning ticket.

Ans. Total no. of lottery tickets = 500

No. of prize winning tickets = 10

P (Prize winning tickets) = 10500=150


3 Marks Questions

1. 1500 families with 2 children were selected randomly and the following data were recorded:

No. of girls in a family

No. of families

2

1

0

475

814

211

Compute the probability of a family, chosen at random, having:
(i) 2 girls (ii)1 girl (iii) No girl
Also check whether the sum of these probabilities is 1.

Ans No. of families having 2 girls = 475

P (Family having 2 girls) = 4751500=1960

(ii) No of families having 1 girl = 814

P(Family having 1 girl) = 8141500=407750

(iii) No. of families having no girl = 211

P (Family having no girl) = 2111500

  • : Sum of all probabilities = 1960+407750+2111500

= 475+814+2111500=15001500= 1

Yes, the sum of probabilities is 1.


2. An organization selected 2400 families at random and surveyed them to determine a relationship between income level and the number of vehicles in a family. The information gathered is listed in the table below:

Monthly income (in Rs.)

Vehicles per family

0

1

2

Above 2

Less than 7000

7000 – 10000

10000 – 13000

13000 – 16000

16000 or more

10

0

1

2

1

160

305

535

469

579

25

27

29

59

82

0

2

1

25

88

Suppose a family is chosen. Find the probability that the family chosen is:

  1. earningRs. 10000 – 13000 per month and owning exactly 2 vehicles.
  2. earningRs. 16000 or more per month and owning exactly 1 vehicle.
  3. earning less than Rs. 7000 per month and does not own any vehicle.
  4. earningRs. 13000 – 16000 per month and owning more than 2 vehicles.
  5. not more than 1 vehicle.

Ans (i) P (earning Rs. 10000 – 13000 per month and owning exactly 2 vehicles) = 292400
(ii) P (earning Rs. 16000 or more per month and owning exactly 1 vehicles) = 5792400
(iii) P (earning Rs. 7000 per month and does not own any vehicles) = 102400=1240
(iv) P (earning Rs. 13000 – 16000 per month and owning more than 2 vehicles) = 252400=196
(v) P (owning not more than 1 vehicle) =
20622400=10311200


3. The marks obtained by 30 students is given in the following table:

Marks 70 58 60 52 65 75 68

No. of Students 3 5 4 7 6 2 3

Find the Probability that a student secures

(i) 60 marks (ii) 75 marks (iii) Less than 60 marks

Ans. Total no. of students = 30

No. of students securing 60 marks = 4

(i) P (Students securing 60 marks) = 430=215

(ii) No. of students securing 75 marks = 2

P (Students securing 75 marks) = 230=115

(iii) No. of students securing less than 60 marks = 5+7 = 12

P (Students securing less than 60 marks) = 1230=25


4. A tyre manufacturing company kept a record of the distance covered shows the results of 1000 tyres

Distance(in km) Less then 4000 4000 to 9000 9001 to 14000 More then 14000

Frequency 20 210 325 445

If you buy a tyre of this company. What is the Probability that

(i) it will need to be replaced before it has covered 4000 km

(ii) it will last more than 9000 km

(iii) it will need to be replaced after it has covered somewhere between 4000 km and 14000 km

Ans. (i) No. of tyres which covered distance less than 4000 km = 20

Total no. of tyres = 1000

Required probability P(E)=201000=150

(ii) No. of tyres needed to replaced more then 9000 km = 325+445=770

Required Probability = 7701000=77100=0.77

(iii) No. of tyres needed to replaced between 4000 km, to 14,000km.

=210+325+445=980

Required probability =9801000=0.98


5. The ages of 30 workers in a factory are as follows

Age (in yrs) 21-23 23-25 25-27 27-29 29-31 31-33 33-35

workers 3 4 5 6 5 4 3

Find the probability that the age of a works lies in the interval

(i) 27-29

(ii) 29-35

(iii) 21-27

Ans. I Part

The no. of workers lies in the interval 27-29 are = 6

Total no. of workers = 30

Required probability = 630=15

II Part

No. of workers having age between 29 - 35 = 5+4+3 = 12

Total no. of workers = 30

Required Probability = 1230=25

III Part

No. of workers having age between 21 -27 = 3+4+5=12

Total no. of workers = 30

Required Probability = 1230=25


6. A die is thrown once. Find the probability of getting

(i) a prime number

(ii) a number less then 5

Ans. When a die is thrown, then outcomes are 1, 2, 3, 4, 5, 6

(i) Prime numbers are = 2, 3, 5

Frequency of happening prime number is 3

The probability of getting prime number =