Important Questions for CBSE Class 6 Maths Chapter 10 - Mensuration
CBSE Class 6 Maths Important Questions Chapter 10 - Mensuration - Free PDF Download
Ch-10 Mensuration
- The side of a square is 12 m. Its perimeter is
- 144 m
- 48 m
- 24 m
- 36 m
- The shape of your class room blackboard is
- circle
- equilateral triangle
- square
- rectangle
- Which figure encloses more area: a square of side 2 cm ; a rectangle of side 3 cm and 2 cm ;An equilateral triangle of side 4 cm?
- None of these
- square
- equilateral triangle
- rectangle
- The perimeter of the given figure is
- 70 cm
- None of these
- 60 cm
- 100 cm
- The area of square is 100 . Its side is
- 5 cm
- 10 cm
- 20 cm
- 10.5 cm
Match the following:-
Shapes Perimeter a. i. 15 b. ii. 8 c. iii. 24 d. iv. 12 Fill in the blanks:-
- _____ is a rectangle whose all sides are equal.
- The amount of surface enclosed by a figure is called its ____.
- For fencing the plot, we need to calculate its _____.
- _____ is the sum of all sides.
State True or False:-
- For tiling a rectangular Plot, we must calculate its area.
- Length and breadth of a Rectangle are 1.5m and 1m. Area is 1.5m2.
- The Perimeter of a square is 4 times the length of the side.
- To find the length of fencing the square playground we must find its Perimeter.
- Find the area of the rectangle whose side are :3 cm and 4 cm
- Find the area of the rectangle whose side are :12 m and 21 m
Find the perimeter of each of the following figures given below?
- Find the perimeter of the following figure?
- Find the perimeter of the following figure given below.
- Find the area of the following figure:
- The length of rectangle is thrice its breadth and its perimeter is 48cm. Find length and breadth of rectangle.
Answer
- (b) 48 m, Explanation: Perimeter of square =
here length = 12 m
so, the perimeter = 4 * 12
= 48 m
- (b) 48 m, Explanation: Perimeter of square =
- (d) rectangle, Explanation: Shape of the blackboard in class room is rectangle as the length of the blackboard is more than the breadth it.
- (c) equilateral triangle, Explanation: Area of square = , when l = 2 cm , Area = 4 cm2
Area of rectangle = , when l = 3 cm and b = 2 cm , Area = = 6 cm2
Area of an equilateral triangle = , when a = 4 cm , Area = 6.93 cm2
so, the area of eqilateral traiangle is more
- (c) equilateral triangle, Explanation: Area of square = , when l = 2 cm , Area = 4 cm2
- (d) 100 cm, Explanation: Perimeter means addition of all sides.
So Perimeter of given triangle = 30 + 30 + 40 = 100 cm
- (d) 100 cm, Explanation: Perimeter means addition of all sides.
- (b) 10 cm, Explanation: Area of square = here area = 100 so the lenght is = length = 10 cm
- iii
- iv
- i
- ii
- Square
- area
- Perimeter
- Perimeter
- True
- True
- True
- True
- Area of the rectangle = Length × Breadth = 3 × 4 cm = 12 sq cm
- Area of the rectangle = Length × Breadth = 12 m × 21 m = 252 sq m
- Perimeter = 3 cm + 3 cm + 3 cm + 3 cm + 3 cm
= 15 cm - Perimeter = 1 cm + 4 cm + 0.5 cm + 2.5 cm + 2.5 cm + 0.5 cm + 4 cm
= 15 cm - Perimeter = 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm
= 52 cm
- Perimeter = 3 cm + 3 cm + 3 cm + 3 cm + 3 cm
- Perimeter
= AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3 cm
= 28 cm - Perimeter
= AB + BC + CD + DA
= 5 cm + 5 cm + 5 cm + 5 cm = 20 cm - Full-filled squares = 2
half-filled squares = 4
Area covered by full squares = 2 1 sq unit = 2 sq units
Area covered by half squares = 4 sq unit = 2 sq units
Total Area = 2 sq units + 2 sq units = 4 sq units - Let the breadth of rectangle = b
length of rectangle = 3b
Perimeter of rectangle
24 = 4b
breadth = 6cm
length = 3b