CBSE Class 10 Maths Chapter-6 Triangles – Free PDF Download
Free PDF download of Important Questions with Answers for CBSE Class 10 Maths Chapter 6 – Triangles prepared by expert Maths teachers from latest edition of CBSE(NCERT) books only by CoolGyan to score more marks in CBSE board examination.
CBSE Class 10 Maths Chapter-6 Triangles Important Questions
CBSE Class 10 Maths Important Questions Chapter 6 – Triangles
2 Mark Questions
1. In the given figures,
and 
Find
(i) 
(ii) 
(iii) 
(iv) 
(v) 
Ans. (i) 
(ii) 
(iii) 
(iv)
(v) 
2. 
and their areas are respectively 64 cm2 and 121 cm2. If EF = 15.4 cm, find BC.
Ans. 
[
the ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding sides]
=11.2 cm
3. ABC is an isosceles right triangle right-angled at C. Prove that 
Ans. In right-angled 
[By Pythagoras theorem]
4. In the figure, DE||AC and 
, prove that
Ans. In 
[By Thales’s Theorem]
Also 
from (i) and (ii), we get
[By the converse of Thales’s Theorem]
5. The hypotenuse of a right triangle is 6 m more than the twice of the shortest side. If the third side is 2m less than the hypotenuse. Find the side of the triangle.
Ans. Let shortest side be 
in length
Then hypotenuse 
And third side = 
We have,
Hence, the sides of triangle are 10 m, 26 m and 24 m.
6. PQR is a right triangle right angled at P and M is a point on QR such that PM
QR. Show that 
Ans. 
is a right triangle right angled at P and 
i. e.,
7. In the given figure, 
and 
Prove that 
Ans. In 
In 
From (i) and (ii), we get
From 
8. In figure, DE||BC, Find EC.
Ans. 
9. In the given figure, ABC and AMP are two right-angled triangles, right angled at B and M respectively, prove that
Ans. In 
and DAMP,
(Each 
)
are equiangular
i.e.,
10. In the given figure, OA × OB=OC × OD or 
prove that 
and 
Ans. In 
and 
And 
[Vertically opposite Angles]
[Corresponding angles of similar 
]
11. In the given figure, DE||BC and AD=1 cm, BD = 2 cm. What is the ratio of the area of to the area of 
Ans. in
Also 
Hence, 
12. A right-angle triangle has hypotenuse of length p cm and one side of length q cm. If p – q =1, Find the length of third side of the triangle.
Ans. Let third side = x cm
Then by Pythagoras theorem,
13. The length of the diagonals of a rhombus are 24 cm and 10 cm. Find each side of rhombus.
Ans. 
From right-angled
Hence each side = 13 cm
14. In an isosceles right-angled triangle, prove that hypotenuse is 
times the side of a triangle.
Ans. Let hypotenuse of right-angled
and equal sides of 
By Pythagoras theorem,
15. In figure, express x in terms of a, b, c.
Ans. 
16. The perimeter of two similar triangle ABC and PQR are respectively 36 cm and 24 cm. If PQ=10 cm, find AB.
Ans. 
17. In the given figure, DE||BC. If 
find the value of 
Ans. In the given figure,
18. The hypotenuse of a right-angled triangle is p cm and one of sides is q cm. if p = q+1, find the third side in terms of q.
Ans. Let third side be 
From (i) and (ii), we get
19. In the given figure,
and AB = 5 cm, find the value of DC.
Ans. In 
and 
[Vertically opposite angles]
[Given]
[By SAS similarity]
20. In 
and D is a point on side AC, such that 
. Prove that BD = BC.
Ans. Given: Ain which AB = AC, D is a point on BC
To prove: BD = BC
Proof: [given]
In and 
and
[SAS similarity]
