## NCERT Solutions for Class 8 Chapter 5 Data Handling -Free PDF Download

Free PDF download of NCERT Solutions Maths Class 8 Solutions Chapter 5 – Data Handling solved by Expert Maths Teachers on CoolGyan.Org. All Chapter 5 – Data Handling Questions with Solutions for NCERT to help you to revise complete Syllabus and Score More marks.

Maths Revision Notes for Class 8

Chapter Name | Data Handling |

Chapter | Chapter 5 |

Exercise | Exercise 5.3 |

Class | Class 8 |

Subject | Maths NCERT Solutions |

Board | CBSE |

TEXTBOOK | CBSE NCERT |

Category | NCERT Solutions |

**NCERT SOLVED**

**1. List the outcomes you can see in these experiments.**

**(a) Spinning a wheel **

**(b) Tossing two coins together**

**Ans. (a)** There are four letters A, B, C and D in a spinning wheel. So there are 4 outcomes.

**(b)** When two coins are tossed together. There are four possible outcomes HH, HT, TH, TT.

(Here HT means head on first coin and tail on second coin and so on.)

**2. When a die is thrown, list the outcomes of an event of getting:**

**(i) (a) a prime number **

**(b) not a prime number**

**(ii) (a) a number greater than 5 **

**(b) a number not greater than 5**

**Ans. (i)** (a) Outcomes of event of getting a prime number are 2, 3 and 5.

(b) Outcomes of event of not getting a prime number are 1, 4 and 6.

**(ii)** (a) Outcomes of event of getting a number greater than 5 is 6.

(b) Outcomes of event of not getting a number greater than 5 are 1, 2, 3, 4 and 5.

**3. Find the:**

**(a) Probability of the pointer stopping on D in (Question 1 (a)).**

**(b) Probability of getting an ace from a well shuffled deck of 52 playing cards.**

**(c) Probability of getting a red apple. (See figure below)**

**Ans**. **(a)** In a spinning wheel, there are five pointers A, A, B, C, D. So there

are five outcomes. Pointer stops at D which is one outcome.

So the probability of the pointer stopping on D = 1515

**(b)** There are 4 aces in a deck of 52 playing cards. So, there are four events of getting an ace.

So, probability of getting an ace = 452=113452=113

**(c)** Total number of apples = 7

Number of red apples = 4

Probability of getting red apple = 4747

**4. Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of:**

**(i) getting a number 6.**

**(ii) getting a number less than 6.**

**(iii) getting a number greater than 6.**

**(iv) getting a 1-digit number.**

**Ans**. **(i)** Outcome of getting a number 6 from ten separate slips is one.

Therefore, probability of getting a number 6 = 110110

**(ii)** Numbers less than 6 are 1, 2, 3, 4 and 5 which are five. So there are 5 outcomes.

Therefore, probability of getting a number less than 6 = 510=12510=12

**(iii)** Number greater than 6 out of ten that are 7, 8, 9, 10. So there are 4 possible outcomes.

Therefore, probability of getting a number greater than 6 = 410=25410=25

**(iv)** One digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9 out of ten.

Therefore, probability of getting a 1-digit number = 910910

**5. If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a none-blue sector?**

**Ans. **There are five sectors. Three sectors are green out of five sectors.

Therefore, probability of getting a green sector = 3535

There is one blue sector out of five sectors.

Non-blue sectors = 5 – 1 = 4 sectors

Therefore, probability of getting a non-blue sector = 4545

**6. Find the probability of the events given in Question 2.**

**Ans. **When a die is thrown, there are total six outcomes, i.e., 1, 2, 3, 4, 5 and 6.

**(i) (a)** 2, 3, 5 are prime numbers. So there are 3 outcomes out of 6.

Therefore, probability of getting a prime number = 36=1236=12

**(b)** 1, 4, 6 are not the prime numbers. So there are 3 outcomes out of 6.

Therefore, probability of getting a prime number = 36=1236=12

**(ii)** **(a)** Only 6 is greater than 5. So there is one outcome out of 6.

Therefore, probability of getting a number greater than 5 = 1616

**(b)** Numbers not greater than 5 are 1, 2, 3, 4 and 5. So there are 5 outcomes out of 6.

Therefore, probability of not getting a number greater than 5 = 56