## NCERT Solutions for Class 8 Chapter 16 Playing with Numbers -Free PDF Download

Free PDF download of NCERT Solutions Maths Class 8 Solutions Chapter 16 – Playing with Numbers solved by Expert Maths Teachers on CoolGyan.Org. All Chapter 16 – Playing with Numbers Questions with Solutions for NCERT to help you to revise complete Syllabus and Score More marks.

Maths Revision Notes for Class 8

Chapter Name | Playing with Numbers |

Chapter | Chapter 16 |

Exercise | Exercise 16.2 |

Class | Class 8 |

Subject | Maths NCERT Solutions |

Board | CBSE |

TEXTBOOK | CBSE NCERT |

Category | NCERT Solutions |

**NCERT SOLVED**

**1. If 21 y5 is a multiple of 9, where y is a digit, what is the value of y?**

**Ans.** Since 21*y*5^{ }is a multiple of 9.

Therefore according to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.

Since 21*y*5 is a multiple of 9.

**2. If 31 z5 ^{ }is a multiple of 9, where z is a digit, what is the value of z? You will find that there are two answers for the last problem. Why is this so?**

**Ans.** Since 31*z*5 is a multiple of 9.

Therefore according to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.

If

Hence 0 and 9 are two possible answers.

**3. If 24 x is a multiple of 3, where x is a digit, what is the value of x?**

**(Since 24 x is a multiple of 3, its sum of digits 6 + x is a multiple of 3; so 6 + x is one of these numbers: 0, 3, 6, 9, 12, 15, 18, … .But since x is a digit, it can only be that**

6 + x = 6 or 9 or 12 or 15. Therefore, x = 0 or 3 or 6 or 9. Thus, x can have any of (four different values.)

**Ans.** Since is a multiple of 3.

Therefore according to the divisibility rule of 3, the sum of all the digits should be a multiple of 3.

Since is a digit.

Thus, can have any of four different values.

**4. If 31 z5^{ }is a multiple of 3, where z is a digit, what might be the values of z?**

**Ans.** Since 31*z*5 is a multiple of 3.

Therefore according to the divisibility rule of 3, the sum of all the digits should be a multiple of 3.

Since is a digit.

If

If

If

Hence 0, 3, 6 and 9 are four possible answers.